During this course 2011 - 2012 MATHEMATICS is being taught for 4º ESO.

11 / 11 / 11 A QUESTION TO THINK ABOUT

  sin30=1/2 sin30=1/2 sin30=1/2 sin30=1/2 sin30=1/2 sin30=1/2 sin30=1/2 sin30=1/2 sin30=1/2 sin30=1/2 sin30=1/2
m

If x is a positive angle smaller than 180° and cos(x) = -1/3, then sin(x) =

  A) -2/3             B)
2√2 / 3            C) 8/9             D) -8/9             E) 4/9 

m
cos60=1/2 cos60=1/2 cos60=1/2 cos60=1/2 cos60=1/2 cos60=1/2 cos60=1/2 cos60=1/2 cos60=1/2 cos60=1/2 cos60=1/2

4 comments:

  1. I hadn't answered before to see if anyone else was gonna answer because I don't wanna be the only one who answers the problems of the week.
    The answer is c) because:
    90º<x<180º, so 2nd quadrant, so cos is negative and sine positive.
    sin^2 + cos^2 = 1; We solve it and we get sine = 8/9

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  2. Nicolás González MenesesDecember 15, 2011

    Imanol's explanation is good and easy to understand, but he's commited a mistake on the last equation. 8/9 is not the sine, it's the sin^2. So, to complete the equation, you must calculate the square root of 8/9, that is the option b.

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  3. Nicolás, you are right. Imanol told me the right solution last wednesday, but he didn´t post it to provoke discussion. Thank you both for your interesting ideas.

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  4. Alfredo SampedroDecember 16, 2011

    The function sine is positive in the first and second quadrant.

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